1 solutions
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1
#include <bits/stdc++.h> using namespace std; int n,a[10000],dp[10000][10000]; int main(){ scanf("%d",&n); for(int i = 1;i<=n;i++)scanf("%d",&a[i]); for(int len = 3;len<=n;len++) for(int i = 1;i+len-1<=n;i++){ int j = i+len-1; dp[i][j] = 1e9; for(int k = i+1;k<j;k++)dp[i][j] = max(dp[i][j],dp[i][k]+dp[k][j]+a[i]*a[k]*a[j]); } printf("%d",dp[1][n]); return 0; }
Information
- ID
- 764
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 10
- Tags
- (None)
- # Submissions
- 8
- Accepted
- 4
- Uploaded By