1 solutions
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1
#include <bits/stdc++.h> using namespace std; int n,v,a[40],dp[20005]; int main(){ scanf("%d%d",&v,&n); for(int i = 1;i<=n;i++)scanf("%d",&a[i]); for(int i = 1;i<=n;i++) for(int j = v;j>=a[i];j--)dp[j] = max(dp[j],dp[j-a[i]]+a[i]); printf("%d",v-dp[v]); return 0; }
- 1
Information
- ID
- 743
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 9
- Tags
- (None)
- # Submissions
- 13
- Accepted
- 3
- Uploaded By