1 solutions

  • 1
    @ 2025-4-26 16:02:39
    #include <bits/stdc++.h>
    using namespace std;
    int n,m,dp[20005],a[105];
    int main(){
    	scanf("%d%d",&n,&m);
        for(int i = 1;i<=n;i++)scanf("%d",&a[i]);
        dp[0] = 1;
        for(int i = 1;i<=n;i++)
    		for(int j = m;j>=a[i];j--)dp[j]+=dp[j-a[i]];
        printf("%d",dp[m]);
        return 0;
    }
    
    • 1

    Information

    ID
    744
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    10
    Tags
    (None)
    # Submissions
    3
    Accepted
    3
    Uploaded By