1 solutions
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1
好吧,既然这么多人都不理解的话,那本人就勉强发一篇关于此题的题解吧
#include<bits/stdc++.h> using namespace std; double a,b,c,d,s; double fc(double x){ return a*x*x*x+b*x*x+c*x+d; } int main(){ double l,r,m,x1,x2; scanf("%lf%lf%lf%lf",&a,&b,&c,&d); for(int i = -100;i<100;i++){ l = i; r = i+1; x1 = fc(l); x2 = fc(r); if(!x1){ printf("%.2lf ",l); s++; } if(x1*x2<0){ while(r-l>=0.001){ m = (l+r)/2; if(fc(m)*fc(r)<=0)l = m; else r = m; } printf("%.2lf ",r); s++; } if(s == 3)break; } return 0; }
- 1
Information
- ID
- 667
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 10
- Tags
- # Submissions
- 4
- Accepted
- 3
- Uploaded By