1 solutions

  • 1
    @ 2025-5-24 14:23:23
    #include <bits/stdc++.h>
    using namespace std;
    int n,x,y,ans;
    int main(){
    	scanf("%d%d%d",&n,&x,&y);
    	if(!x)printf("0");
    	if(y/x>n){
    		printf("0");return 0;
    	}
    	y%x?ans = n-y/x-1:ans = n-y/x;
    	printf("%d",ans);
    	return 0;
    }
    
    • 1

    Information

    ID
    120
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    10
    Tags
    # Submissions
    7
    Accepted
    2
    Uploaded By